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Print all Jumping Numbers smaller than or equal to a given value
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WebFeb 1, 2024 · One Simple Solution is to traverse all numbers from 0 to x. For every traversed number, check if it is a Jumping number. If yes, then print it. Otherwise ignore it. An Efficient Solution can solve this problem in O (k) time where k is number of Jumping Numbers smaller than or equal to x. The idea is use BFS or DFS . WebMay 24, 2015 · Once you have that, we can simply do: if (num >= 1 && num <= 12) { System.out.format ("The name of month number %d is %s\n", num, months [num-1]); } … WebIn computer programming, comments are a portion of the program that are completely ignored by Java compilers. They are mainly used to help programmers to understand the code. For example, // declare and initialize two variables int a =1; int b = 3; // print the output System.out.println ("This is output"); Here, we have used the following comments, download google per windows 7